mysql - What is wrong with this php code? LEFT OUTER JOIN -


i have table users ("usuarios") , table friends ("amigos"), wanna friends of user id, don't receive error can't see results...

<?php   $host     = 'localhost';   $username = 'root';   $pwd      = '';   $db       = "lyne";    $con = mysqli_connect($host,$username,$pwd,$db) or die('unable connect');   if(mysqli_connect_error($con)) {     echo "failed connect database ".mysqli_connect_error();   }    $id     = $_get['prefid'];   $sql    = "select a.*, u.nome amigos left outer join usuarios u on(u.usu_id = a.usuario_dois) usuario_um ='$id'";   $result = mysqli_query($con,$sql);    if($result) {     while($row=mysqli_fetch_array($result)) {       $data[]=$row;     }     print(json_encode($data));   }          mysqli_close($con); ?>

i receive blank screen (i'm testing get, post when done) sorry bad eng

solved, problem not code. in users list have people accents in names, "andré", , when user friend of 1 of these people, dont work, dont know why. that's it.


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