php - Unable to use an array as an array? -


i in process of building software download site company.

however, have come across problem unsure how past.

i retrieving information table particular software release , placing them in multidimensional array. trying run foreach (i have tried loop) against array , error shown below: error message

when run var dump against original array, this:

var dump results

so confused don't know i'm missing or going wrong. reason why want run can filter array 1 dimensional array.

below code main web page

<?php   //displays list of companies in 2 columns   $versionaccess = versionaccess::findaccess($relid);//this gets set earlier in webpage   $count = count($versionaccess);   var_dump($versionaccess);   foreach ($versionaccess $va)   {     if ($va->company_access != '0')     {       $versionacc[] = $va->comapny_id;     }   }   foreach ($company $compaccess)   {     $compaccessid = $compaccess->company_id;     if (in_array($compaccessid, $versionacc))     {       $access = 'checked disabled';     }     else { $access = 'disabled'; }     $accessname = 'access'.$compaccessid;     if ($ctr % 2 == 0)     {       echo '<td>'.$compaccess->company_name.':</td>';       echo '<td><label class="switch"><input type="checkbox" name="'.$accessname.'" value="1" '.$access.'><span class="slider round"></span></label></td>';       echo '</tr>';     }     else     {       if ($ctr < $compcount)       {          echo '<tr>';          echo '<td>'.$compaccess->company_name.':</td>';          echo '<td><label class="switch"><input type="checkbox" name="'.$accessname.'" value="1" '.$access.'><span class="slider round"></span></label></td>';       }       else       {          echo '<tr>';          echo '<td>'.$compaccess->company_name.':</td>';          echo '<td><label class="switch"><input type="checkbox" name="'.$accessname.'" value="1" '.$access.'><span class="slider round"></span></label></td>';          echo '</tr>';        }     }     $ctr++;   } ?>

the function brings data database is:

public static function findaccess($accessid) //find version access in database {     return self::findquery("select * version_access version_id = '$accessid'"); }

the findquery method:

public static function findquery($sql) {     global $database;      $resultset = $database->query($sql);     $objectarray = array();     while ($row  = mysqli_fetch_array($resultset))     {         $objectarray[] = self::instant($row);     }     return $objectarray; }

i still relatively new , appreciated.


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