how to remove last 3 letters from string including spaces in r -
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- remove seconds time in r 5 answers
i have following dataframe in r
date count 2016-12-30 17:25:00 34 2016-12-04 10:25:00 31 i want change format following , want remove seconds date
desired dataframe be
date count 30-12-2016 17:25 34 04-12-2016 10:25 31 i doing following because of space inbetween date returning me wrong output
substr(df$date,1,nchar(df$date)-3) how can in r?
we convert posixct , format
df1$date <- format(as.posixct(df1$date), "%d-%m-%y %h:%m") df1$date #[1] "30-12-2016 17:25" "04-12-2016 10:25"
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