unix - grep command not match start of new line with another regex -


i have file content:

path=/nfs/location/alex  path = /nfs/location/  alex/nfs/location  /nfs/location/ # /nfs/location/ #alex /nfs/location alex # d /nfs/location /nfs/location

i want print line path starts , don't contain #

/nfs/location/

in example line 3 not match

i wrote unix commad:

grep -re ([^#.*]|^[^0-9aa-zz]/nfs/location/ .

but lines # appear

you want select lines /nfs/location additional requirement:
should on start of line or non-alnum character must in front of it. can use or in expression:

echo "path=/nfs/location/alex path = /nfs/location/ alex/nfs/location /nfs/location/" | grep -e "(^|[^0-9a-za-z])/nfs/location"

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