java - Recursive method that prints all of the digits in a number that or greater than the first digit and lower than the last digit -

the problem:

i'm trying write recursive method prints of digits in number or greater first digit , lower last digit. accomplished write recursive method prints of digits or lower last digit. can't figure out how check if digit grater first digit.

examples:

for print(325648) print 5, 6, 4.

for print(237) print 3.

for print(925648) not print digit.

this code:

public static void print(int n) {      print(n,n%10); } private static void print(int n,int lastdigit) {     if(n==0)         return;     if(n%10<lastdigit)         system.out.println(n%10);     print(n/10,lastdigit); } 

the requirement of method:

• not allowed use loops(or methods loops).
• allowed use 1 recursive transition.
• the length of number not known.
• the method can change number, @ end of operation number should same @ beginning.

please note: not homework assignment! i'm writing method practice exam talking tomorrow.

the idea here recurse dividing 10 until number reduced first digit. on return through recursions have first digit return value , compare quite easily.

private static void print( int n ){     print( n/10, n%10 ); }  private static int print( int n, int ld ){     if( n < 10 ) return n;     int digit = n % 10;     int first = print( n/10, ld );     if( digit < ld && digit > first )         system.out.println( digit );     return first; }