c++11 - C++: Confusion on auto deduction using a const against an array -
example code:
int aa[] = {1,2,3,4}; auto const p = aa;
why p
deduced int *const
instead int const *
?
because aa
non-const array, decay pointer-to-non-const , therefore p
deduced pointer-to-non-const. , because declared p
const, const pointer-to-non-const.
declaring variable const make variable const. doesn't make type of variable different (pointer-to-const , pointer-to-non-const different types) except in sense may const qualified version of same type.
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