mysql - Display an image from PHP using header and echo -


for school project have save images in mysql database , show images on website. so, use following code save images:

$link = $link = new pdo('mysql:host=localhost;dbname=mydatabase', 'root', '');  $user = $_post['user']; $image = [];  $image = $_files['file']; $image['string_scape'] = $link->quote(file_get_contents($_files['file']['tmp_name']));  $link->query('insert userimage values(null, "'.$image['string_scape'].'", "'.$image['type'].'", '.$image['size'].', '.$user.', now())') or die (print_r($link->errorinfo()));  $link = null; 

this table made images:

+------------+----------+------+-----+---------+----------------+ | field      | type     | null | key | default |          | +------------+----------+------+-----+---------+----------------+ | id         | int(11)  | no   | pri | null    | auto_increment | | file       | longblob | no   |     | null    |                | | type       | text     | no   |     | null    |                | | size       | int(11)  | no   |     | null    |                | | user       | int(11)  | no   |     | null    |                | | date_added | datetime | no   |     | null    |                | +------------+----------+------+-----+---------+----------------+ 

and show images use following code:

//php file "show-image.php" $link = new pdo('mysql:host=localhost;dbname=distribuidora', 'root', ''); $result = $link->query('select * userimage id = '.$_get['id']) or die (print_r($link->errorinfo()));  $image = $result->fetch(pdo::fetch_assoc);  header("content-type:".$image["type"]); header("content-length:".$image["size"]); echo $image["file"]; 

the html:

<img src="show-image.php?id=1" alt="image" /> 

this how i've done last year , used work fine, since last week can't make image shown. i've tried different headers , different solutions given in other questions in here, still won't work.

i think error in $image = $_files['file']; u should name file $image = $_files['file']['name']; , change html <img src="show-image.php?id=1" alt="image" name='name' />


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