python - Sorting dictionary with alphanumeric keys in natural order -

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• does python have built in function string natural sort? 12 answers

i have python dictionary:

d = {'a1': 123, 'a2': 2, 'a10': 333, 'a11': 4456} 

when sort dictionary using ordereddict following output:

from collections import ordereddict ordereddict(sorted(d.items())) # output # ordereddict([('a1', 123), ('a10', 333), ('a11', 4456), ('a2', 2)]) 

is there way in natural order:

ordereddict([('a1', 123), ('a2', 2), ('a10', 333), ('a11', 4456)]) or  {'a1': 123, 'a2': 2, 'a10': 333, 'a11': 4456} 

thanks.

you're in luck: natsort module can help. first, install using:

pip install natsort 

now, can pass d.keys() natsort.natsorted, , build new ordereddict.

import natsort collections import ordereddict  d = {'a1' : 123,       'a2' : 2,       'a10': 333,       'a11': 4456} keys = natsort.natsorted(d.keys())     d_new = ordereddict((k, d[k]) k in keys) 

a shorter version involves sorting d.items() (got idea romanperekhrest's answer):

d_new = ordereddict(natsort.natsorted(d.items())) 

---

d_new ordereddict([('a1', 123), ('a2', 2), ('a10', 333), ('a11', 4456)])