python - can't pass arguments to running flask webserver -


from android app make pictures raspberry pi via ssh , try upload them website flask. before app ask users enter code , want code in url, why need argparse.

i want server running , in meantime want pass new urls script creates pages. when i'm running pitonka.py , add arguments, tnb_flask.py doesn't them.

what can solution?

thanks in advance!

pitonka.py:

   flask import flask    import argparse    import random      tenor = ''    def tuzok():           if args.arg_name == "az":           else:                  tenor = ''                  if args.arg_name == '':                         tenor = ''                  else:                         tenor = args.arg_name           print("tenor", tenor)     if __name__ == "__main__":           parser = argparse.argumentparser()           parser.add_argument("arg_name", help="enter function's name", type=str, default ="az")           args = parser.parse_args()           tuzok() 

tnb_flask.py

   flask import flask     pitonka import *    app = flask(__name__)     @app.route('/')    def index():           denis = 25           print("tenor:+", tenor, "+")           to_ret = "tenor:+" + tenor+  "+\n" + str(denis)           return to_ret      if __name__ == "__main__":           app.run(debug=true)           if tenor != "az":                  print("nem az!!!")                  @app.route('/tuna/<tenor>')                  def index__(numbi):                         return 'working: args.arg_name %s' % tenor           else:                  print("azzal egyezik meg") 


Comments

Popular posts from this blog

resizing Telegram inline keyboard -

command line - How can a Python program background itself? -

php - "cURL error 28: Resolving timed out" on Wordpress on Azure App Service on Linux -