r - Can't split dataframe into equal buckets preserving order without introducing Xn. prefix -

i trying split ordered data frame 10 equal buckets. following works introduces x1., x2., x3. ... prefix each bucket, prevents me iterating on buckets sum them.

num_dfs <- 10 buckets<-split(df, rep(1:num_dfs, each = round(nrow(df) / num_dfs))) 

produces df[10] looks like:

$`10`        predicted_duration actual_duration 177188         23.7402944               6 466561         23.7402663              12 479556         23.7401721               5 147585         23.7401666              48 

here's crude code using try sum groups.

for (i in c(1,2,3,4,5,6,7,8,9,10)){   p<-sum(as.data.frame(df[i],row.names=null)$x1.actual_duration) # x1., x2.,   print(paste(i,"=",p)) } 

how remove xn. grouping prefix or programmatically reference using index i?

here's similar reproducible example:

df<-data.frame(actual_duration=sample(100)) num_dfs <- 10 df_grouped<-as.data.frame(split(df, rep(1:num_dfs, each = round(nrow(df) / num_dfs))))  (i in c(1,2,3,4,5,6,7,8,9,10)){   p<-sum(df[i]$actual_duration) # not work because postfix .1, .2.. added r   print(paste(p)) } 

i'm not entirely clear on issue is, if trying sum group couldn't use

 library(tidyverse)  df <- data.frame(actual_duration=sample(100))   df %>%     arrange(actual_duration) %>%     mutate(group = rep(1:10, each = 10)) %>%     group_by(group) %>%     summarise(sums = sum(actual_duration)) 

alternatively if want keep list format

df %>%    arrange(actual_duration) %>%    mutate(group = factor(rep(1:10, each = 10))) %>%    split(., .$group)  %>%    map(., function(x) sum(x$actual_duration))