php - Warning: mysql_fetch_array() expects parameters 1 to be resource, -
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mysql_fetch_array() expects parameter 1 resource (or mysqli_result), boolean given 31 answers hi im trying write data database , code thats meant doing 2 of 'warning: mysql_fetch_array() expects parameter 1 resource, boolean given' , dont know why???? **
<?php $connection = mysql_connect("localhost", "root", ""); // establishing connection server $db = mysql_select_db("burger machine", $connection); // selecting database //mysql query read data $query = mysql_query("select * add", $connection); while ($row = mysql_fetch_array($query)) { echo "<tr>"; echo " <td> {$row['addons_id']} </td>"; echo " <td> <a href=\"ao.php?update={$row['addons_id']}\"> {$row['addons_name']} </a> </td> "; echo " <td> {$row['addons_price']} </td> "; echo " <td> {$row['addons_description']} </td>"; echo "</tr>"; }
use mysqli mysql deprecated , prone sql injections.
use mysqli_query($con , $query);
where $query sql query fetch data , $con connection resource variable.
on side note
in mysql_query(); pass query parameter, not connection.
<?php $connection = mysqli_connect("localhost", "root", ""); // establishing connection server $db = mysqli_select_db( $connection , "burger machine" ); // selecting database //mysql query read data $query = mysqli_query( $connection , "select * add" ); while ($row = mysqli_fetch_array($query)) { echo "<tr>"; echo " <td> {$row['addons_id']} </td>"; echo " <td> <a href=\"ao.php?update={$row['addons_id']}\"> {$row['addons_name']} </a> </td> "; echo " <td> {$row['addons_price']} </td> "; echo " <td> {$row['addons_description']} </td>"; echo "</tr>"; } 
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